Rick, "Your original calculation of the force on a 25sq.m wing was correct with Cl of 1 was correct - 922N. Actually achieving a Cl of 1 is another matter. I suggest you work on 0.7 for a single wing. A twin wing set up could exceed 1 but at the cost of efficiency."
I am at a loss. Do you actually think that another wing affects the coefficient of lift of another separate wing? That is bizarre, kind of like when you falsely claimed that a wing always generated lift.
Rick, "The air speed is only relevant to producing the force on the wing. From a power perspective it is the force in direction of travel to overcome the drag on the boat in that direction and the velocity through the water."
You keep making fundamental mistakes. The moment force the wing is producing has nothing to do with the velocity through the water. . . or direction. . . .
It is a moment, Kg of Force against the drag though. That is why a Newton is 9.8 times the Kg's of Force. Torque.
Rick, "I was being generous with respect to the speed. I assumed the 5mph or (2.1m/s) was actually in the direction you wanted to travel. If you were wanting to go directly to windward the 5mph drops down to about 3.5mph as VMG. It is inevitable that the average cruising boat spends more time on the wind because the VMG is about half the speed it can do reaching. Also more time is spent running than reaching - even if the boat can exceed windspeed on a reach and tacks downwind its VMG downwind is lower than reaching. So there is not much time that a sailing boat will actually be on its fastest point of sailing."
Amazing, first of all, anyone sailing directly into the wind will come to a halt.
Are you unaware that lift on a wing is perpendicular to the wind?
Also despite your babbling about VMG, almost all sailing is done on a reach. Do you even understand the term?
Now I can see why your other posts on polars don't make any sense, that and I can't see your diagrams. Although they are interesting. . .
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Posted by: taladorwood@yahoo.com.au
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